3000+10x+0.2x^2=95x

Solution for 3000+10x+0.2x^2=95x equation:

3000+10x+0.2x^2=95x

We move all terms to the left:

3000+10x+0.2x^2-(95x)=0

We add all the numbers together, and all the variables

0.2x^2-85x+3000=0

a = 0.2; b = -85; c = +3000;
Δ = b2-4ac
Δ = -852-4·0.2·3000
Δ = 4825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4825}=\sqrt{25*193}=\sqrt{25}*\sqrt{193}=5\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-5\sqrt{193}}{2*0.2}=\frac{85-5\sqrt{193}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+5\sqrt{193}}{2*0.2}=\frac{85+5\sqrt{193}}{0.4}
$